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Watts to Amps Calculator

Convert real power in watts to current in amps for DC/resistive loads, single-phase AC, or balanced three-phase AC. AC modes account for power factor, and the three-phase mode explicitly uses line-to-line voltage.

Built by Umer Farooq, CalcsDone founder/developer•Updated September 24, 2026•Calculation aid—not circuit-design approval
Enter electrical values
DC: I=P/V · 1φ: I=P/(V×PF) · balanced 3φ: I=P/(√3×VLL×PF)
W
V
Use the voltage across the load.
Real power
1500 W
Calculated current
12.50 A
load current
Apparent power
1500 VA
for AC, S = P/PF
Electrical-safety boundary: This calculator performs idealized power/current arithmetic. Do not select conductor size, overcurrent protection, disconnects, motor protection, or equipment ratings from this result alone. Applicable electrical codes can require additional rules for continuous loads, motors, temperature, conductor count, terminals, equipment ratings, and other conditions. Use equipment nameplate/manufacturer data and the code adopted in your jurisdiction; use a qualified electrician or engineer where appropriate.
Formulas

How watts are converted to amps

DC / resistive AC

For DC, or an ideal resistive AC load at unity power factor, I = P ÷ V.

Single-phase AC

For real power P, RMS voltage V and power factor PF, I = P ÷ (V × PF).

Balanced three-phase AC

Using RMS line-to-line voltage VLL and line current, I = P ÷ (√3 × VLL × PF). This shortcut assumes a balanced three-phase load.

Apparent power

For the simplified AC model used here, apparent power is S = P ÷ PF in volt-amperes (VA). At PF=1, watts and VA have the same numeric value.

Worked examples

Watts to Amps Calculator Examples

The examples demonstrate the formulas only; they do not specify breaker or conductor sizes.

Resistive load

Power1,500 W
Voltage120 V
Formula1,500 ÷ 120
12.50 A
Arithmetic current for the stated resistive-load inputs.

Single-phase AC

Power3,000 W
Voltage / PF240 V / 0.85
Formula3,000 ÷ (240×0.85)
14.71 A
Apparent power for the same inputs is about 3,529 VA.

Balanced three-phase AC

Power5,000 W
VLL / PF480 V / 0.85
Formula5,000 ÷ (√3×480×0.85)
7.08 A
This is line current under the balanced-load assumption.
Important assumptions

Where a simple watts-to-amps conversion can fail

Power factor must match the load

The uploaded page suggested 0.8–0.9 as a general fallback. That can create false precision. For non-resistive AC loads, use reliable nameplate, datasheet, or measured information when the result matters.

Three-phase must be interpreted correctly

The √3 formula here uses line-to-line voltage and assumes a balanced three-phase system. Unbalanced systems require phase-specific analysis rather than this shortcut.

Motors need more than watts and PF

Motor nameplate current, efficiency, starting/inrush behavior, duty, and applicable motor-circuit rules can matter. A mechanical-output rating is not automatically the electrical input watts used by this formula.

Nominal current is not circuit sizing

A calculated load current does not by itself determine a safe breaker or wire size. The adopted electrical code and equipment instructions control the final design.

Accuracy

Inputs matter as much as the equation

The equations are straightforward, but the answer is only meaningful when the inputs describe the same electrical condition. For AC, watts should represent real input power, voltage should be the appropriate RMS voltage, and power factor should describe the load at the relevant operating point. For balanced three-phase mode, enter line-to-line voltage.

The calculator intentionally does not estimate power factor from appliance type and does not automatically apply a 125% “safety margin.” Code treatment depends on the load and installation. For example, NFPA materials define continuous-load concepts and include 125% provisions in applicable requirements, but that is not a universal instruction to multiply every calculator result by 1.25.

FAQ

Watts to Amps Calculator FAQ

What power factor should I enter?
Use reliable equipment documentation or measured data when available. Use PF=1 only when that assumption is appropriate, such as the ideal resistive-load case. This calculator does not recommend a generic PF for unknown equipment.
Why can AC current be higher than watts divided by volts?
For the single-phase real-power relationship P = V × I × PF, a power factor below 1 means more current is required for the same real power and voltage.
What voltage should I enter for three-phase mode?
Enter RMS line-to-line voltage. The calculator’s √3 relationship is specifically the balanced three-phase line-voltage/line-current form.
Can I use the answer to choose a breaker or wire?
Not by itself. Circuit sizing can depend on code rules, load type and duration, equipment ratings, conductor conditions, terminals, motor requirements and other installation details.
Does this calculate motor current from horsepower?
No. It accepts real electrical input power in watts. A motor’s mechanical output rating is not automatically its electrical input power because efficiency and other characteristics matter.
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